Flask中提供静态文件的实例讲解
1、可以使用send_from_directory从目录发送文件,这在某些情况下非常方便。
from flask import Flask, request, send_from_directory # set the project root directory as the static folder, you can set others. app = Flask(__name__, static_url_path="") @app.route("/js/<path:path>") def send_js(path): return send_from_directory("js", path) if __name__ == "__main__": app.run()
2、可以使用app.send_file或app.send_static_file,但强烈建议不要这样做。
因为它可能会导致用户提供的路径存在安全风险。
send_from_directory旨在控制这些风险。
最后,首选方法是使用NGINX或其他Web服务器来提供静态文件,将能够比Flask更有效地做到这一点。
知识点补充:
如何在Flask中提供静态文件
import os.path from flask import Flask, Response app = Flask(__name__) app.config.from_object(__name__) def root_dir(): # pragma: no cover return os.path.abspath(os.path.dirname(__file__)) def get_file(filename): # pragma: no cover try: src = os.path.join(root_dir(), filename) # Figure out how flask returns static files # Tried: # - render_template # - send_file # This should not be so non-obvious return open(src).read() except IOError as exc: return str(exc) @app.route("/", methods=["GET"]) def metrics(): # pragma: no cover content = get_file("jenkins_analytics.html") return Response(content, mimetype="text/html") @app.route("/", defaults={"path": ""}) @app.route("/<path:path>") def get_resource(path): # pragma: no cover mimetypes = { ".css": "text/css", ".html": "text/html", ".js": "application/javascript", } complete_path = os.path.join(root_dir(), path) ext = os.path.splitext(path)[1] mimetype = mimetypes.get(ext, "text/html") content = get_file(complete_path) return Response(content, mimetype=mimetype) if __name__ == "__main__": # pragma: no cover app.run(port=80)
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