php实现快速对二维数组某一列进行组装的方法小结
本文实例总结了php实现快速对二维数组某一列进行组装的方法。分享给大家供大家参考,具体如下:
问题:
比如我二维数组是这样的:
$user = array( "0"=> array("id"=>100,"username"=>"a1"), "1"=> array("id"=>101,"username"=>"a2"), "2"=> array("id"=>102,"username"=>"a3"), "3"=> array("id"=>103,"username"=>"a4"), "4"=> array("id"=>104,"username"=>"a5"), )
如何快速的获取所有id组成的ids字符串,比如$ids="100,101,102,103,104"; 再者如果我有条件的组装,比如id!=103等这样的,除了循环处理外有没有比较方便快速的方法?
解决方法:
$user = array( "0"=> array("id"=>100,"username"=>"a1"), "1"=> array("id"=>101,"username"=>"a2"), "2"=> array("id"=>102,"username"=>"a3"), "3"=> array("id"=>103,"username"=>"a4"), "4"=> array("id"=>104,"username"=>"a5"), ); /** * @param array $array 数组 * @param string $k 要获取值的key * @param array $rm 要去除的数据 * */ function array_get_v($array, $k, $rm) { if (!trim($k)) return false; preg_match_all("/"$k":(d+)/", json_encode($array), $res); $res = array_diff($res[1],$rm); return implode(",",$res); } print_r(array_get_v($user, "id",array(101)));
运行结果:
100,102,103,104
补充方法:
例1:
$user = array( "0" => array("id" => 100, "username" => "a1"), "1" => array("id" => 101, "username" => "a2"), "2" => array("id" => 102, "username" => "a3"), "3" => array("id" => 103, "username" => "a4"), "4" => array("id" => 104, "username" => "a5"), ); array_walk($user, function($v, $k) use(&$ids){ $ids[$k] = $v["id"]; }); echo implode(",", $ids);
运行结果:
100,101,102,103,104
例2:
<?php function process($v){ //如果要加限制条件,在这里加入即可 if(isset($v["id"])) return $v["id"]; } $user = array( "0" => array("id" => 100, "username" => "a1"), "1" => array("id" => 101, "username" => "a2"), "2" => array("id" => 102, "username" => "a3"), "3" => array("id" => 103, "username" => "a4"), "4" => array("id" => 104, "username" => "a5"), ); $aUser = array_map("process", $user); echo implode(",", $aUser);
运行结果:
100,101,102,103,104
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希望本文所述对大家PHP程序设计有所帮助。